[mythtv] [Q]: CRC detection for packets

[manu]

	Hi all,
I have a problem here. Looking at pespacket.h I see 
    virtual bool HasCRC()     const { return (_pesdata[4] & 0x2) >> 
1; }

But here is a packet I need to parse (here I used dvbsnoop to get it):

raw packet:

------------------------------------------------------------
SECT-Packet: 00000024   PID: 276 (0x0114), Length: 2019 (0x07e3)
Time received: Wed 2008-06-04  14:59:54.114
------------------------------------------------------------
  0000:  92 f7 e0 00 00 d9 2c 32  f2 49 0a 53 55 52 20 
4c   ......,2.I.SUR L
  0010:  45 20 56 49 46 a0 37 30  2e 08 af 00 2e 40 e6 00   E 
VIF.70..... at ..
[snip]
  07c0:  0d 20 0d 54 48 45 20 42  41 43 4b 57 4f 4f 44 53   . .THE 
BACKWOODS
  07d0:  b0 64 00 34 02 53 20 34  3a 1c 20 34 41 c7 20 03   .d.4.S 4:. 
4A. .
  07e0:  86 7d fb

Here is how it is decoded by dvbsnoop:

Guess table from table id...
User_Defined-decoding....
Table_ID: 146 (0x92)  [= User private]
Section_syntax_indicator: 1 (0x01)
private_indicator: 1 (0x01)
reserved: 3 (0x03)
private_section_length: 2016 (0x07e0)
table_id_extension: 0 (0x0000)
reserved: 3 (0x03)
Version_number: 12 (0x0c)
Current_next_indicator: 1 (0x01)  [= valid now]
Section_number: 44 (0x2c)
Last_section_number: 50 (0x32)
Private Data:
      0000:  f2 49 0a 53 55 52 20 4c  45 20 56 49 46 a0 37 30   .I.SUR 
LE VIF.70
      0010:  2e 08 af 00 2e 40 e6 00  19 53 55 52 20 4c 45 
53   ..... at ...SUR LES
 [snip]
      07b0:  48 4f 57 90 19 80 1c 1a  0d 20 0d 54 48 45 20 42   
HOW...... .THE B
      07c0:  41 43 4b 57 4f 4f 44 53  b0 64 00 34 02 53 20 34   
ACKWOODS.d.4.S 4
      07d0:  3a 1c 20 34 41 c7 20                               :. 4A. 
CRC: 59145723 (0x03867dfb)

So as you can see dvbsnoop detects that it has a crc where mythtv 
thinks that it does not.

I also have the reverse problem: pespacket discards packets because 
they have a bad crc but actually they do not have crc.

So my question: what is the correct method to detect if a packet has a 
crc, the one in mythtv seems to be too simplistic.
Thx
Bye
Manu